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A typical GPS (Global Positioning System) satellite orbits at an altitude of 4.0 107 m.?

(a) Find the orbital period of such a satellite. in hours
(b) Find the orbital speed of such a satellite. km/s

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This entry was posted on Wednesday, July 14th, 2010 at 5:59 am and is filed under Global Positioning System. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

One Response to “A typical GPS (Global Positioning System) satellite orbits at an altitude of 4.0 107 m.?”

  1. a) Period is (2pi/sqrt(G*M_E_)) (r^(3/2))

    G is the constant
    M_E_ is mass of the earth
    r is altitude of the satellite+radius of the Earth
    Plug those numbers in to get the period in seconds.
    Then divide the answer be 60 (to get minutes) and 60 again (to get hours).
    The answer will be somewhere around 35

    b. v=sqrt((G*M_E_)/r)
    The numbers are the same as in part a.
    The answer will be in m/s, so divide by 1000 to get km/s
    The answer will be somewhere around 2.7

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